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次稱重足以在 
個硬幣中找到一個壞硬幣（Steinhaus 1999, p. 61）。vos Savant (1993) 給出了一個演算法，用三次稱重在 12 個球中找到一個壞球（此外，還確定壞球是比其他 11 個球重還是輕），Steinhaus (1999, pp. 58-61) 給出了一個 13 個球的演算法。
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